Question

Calculate the energy of an electron in the n = 7 level of a hydrogen atom.

Answer 1

E = $\frac{13.6}{n^2}$ × eV

E = energy , n = 7 , eV = 1.6×10^-19

E = $\frac{13.6}{7^2}$ × 1.6×10^-19 J

E = $\frac{13.6}{49}$ × 1.6×10^-19 J

E = 0.444×10^-19 J