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Answer to Question #161606 in General Chemistry for Willie
Question #161606
If 125 cal of heat is applied to a 60.0-g piece of copper at 25.0 •C , what will the final temperature be ? The specific heat of copper is 0.920 cal/ (g• C)
Expert's answer
Q=mc∆T.
∆T= Q/mc = 125/60 x 0.92 = 2,26449275.
∆T=T2-T1
T2= ∆T + T1 = 25 + 2,26449275 = 27,2644928 °C.
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