If 16 moles of Ba3(PO4)2 are produced, how many moles of Ba(OH)2 are required for the reaction
The stoichiometric equation of reaction is:
3Ba(OH)2 + 2H3PO4 ------> Ba3(PO4)2 + 6H2O
From the balanced equation,
1mol of Ba3(PO4)2 required 3 moles of Ba(OH)2
16moles of Ba3(PO4)2 will require 16 x 3 moles
= 48 moles of Ba(OH)2
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