Question

If a Geiger counter is filled with 1 mol of argon gas at pressure P = 10276 Pa and temperature T = 24.4 degrees C, what is the density p of the gas in this Geiger tube in grams per cubic centimeter?

Answer 1

Solution:

$ρ=\dfrac{PM}{RT}$

argon is 39.8 $(\frac{g}{mole})$

$ρ=\dfrac{(10.276)(39.8)}{(8.314)(273.15+24.4)}$

$ρ=0.165(\frac{g}{L})$

$0.165(\frac{g}{L})*\dfrac{1L}{1000cm^3}=165(\frac{g}{cm^3})$