Question

To burn 456 grams of nonane (C9H20), how many liters of oxygen are needed?

Answer 1

C₉H₂₀+14O₂=9CO₂+10H₂0

$n(C9H20)=\frac{m}{M}=\frac{456}{128.259}=3.56$

$\frac{3.56}{1}=\frac{x}{14}$

x=49.77

$V(O2)=Vm\times n=22.4\times49.77=1114.94$ L