How much Ca OH2 (molecular weight 74) should be added to 200ml of H2O to make an 18%(w/v) solution
%w/v = 18%
Mass of solute= ?
Volume of solution= 200ml= 0.20L
%w/v = mass of solute/litres of solution x 100%
Mass= 18 x 0.20/100
Mass= 0.036g of Ca(OH)2
Molar mass of Ca(OH)2 is 74g/mol
Mole = mass/molar mass
Mole= 0.036/74 = 4.86 x 10-4 mol
Comments
Leave a comment