Enthalpy of combustion is calculated using the following formula,
ΔHrxn0=∑ΔHf0(products)−∑ΔHf0(reactants)
Gasoline
2C8H18(l)+25O2(g)→16CO2(g)+18H2O(l)ΔHc0=4730kJ/g
Methane
CH4g+O2g→CO2g+2H2Ol+ΔHrxn0=[(−393.5−2∗286)−(−74.85)=890.7kJ/g
Methanol
CH3OHg+23O2g→CO2g+2H2Ol=726kJ/g
Ethanol
C2H5OHg+3O2g→2CO2g+3H2Ol=1368kJ/g
Propane
C3H8g+5O2g→3CO2g+4H2Ol=2220kJ/g
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