Question #160788

Find the Enthalpies of Combustion of gasoline (C8H18), methane (CH4), methnol (CH3OH), ethanol (C2H5OH), propane (C3H8) and kerosene (C15H32). Then determine the Energy-to-Pollution Ratios (EPRs) of each fuel and compare them. Discuss which fuels are most rational to use...if we insist upon burnign hydrocarbons to obtain energy.


Expert's answer

Enthalpy of combustion is calculated using the following formula,

ΔHrxn0=ΔHf0(products)ΔHf0(reactants)\Delta H^0_{rxn}=\sum\Delta H^0_f(products)-\sum\Delta H^0_f(reactants)

Gasoline

2C8H18(l)+25O2(g)16CO2(g)+18H2O(l)ΔHc0=4730kJ/g2C_8H_{18(l)}+25O_{2(g)}\to16CO_{2(g)}+18H_2O_{(l)}\newline \Delta H^0_c=4730kJ/g

Methane

CH4g+O2gCO2g+2H2Ol+ΔHrxn0=[(393.52286)(74.85)=890.7kJ/gCH_{4g}+O_{2g}\to CO_{2g}+2H_2O_l+\Delta H^0_{rxn}\newline =[(-393.5-2*286)-(-74.85)\newline= 890.7kJ/g

Methanol

CH3OHg+32O2gCO2g+2H2Ol=726kJ/gCH_3OH_g+\dfrac{3}{2}O_{2g}\to CO_{2g}+2H_2O_l\newline \newline =726kJ/g

Ethanol

C2H5OHg+3O2g2CO2g+3H2Ol=1368kJ/gC_2H_5OH_g+3O_{2g}\to 2CO_{2g}+3H_2O_l\newline =1368kJ/g

Propane

C3H8g+5O2g3CO2g+4H2Ol=2220kJ/gC_3H_{8g}+5O_{2g} \to 3CO_{2g} +4H_2O_l\newline =2220kJ/g





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