Answer to Question #160748 in General Chemistry for Melissa

Question

2. Build a voltaic cell with one beaker containing a solution of nickel (II) nitrate - Ni(NO₃)₂

- with a nickel electrode, and a second beaker containing a solution of zinc chloride - 

ZnCl₂ - with a zinc electrode.

a.  The half reactions

b.  Flow of electrons

c.  Short-form notation

d.  Electric potential (voltage)

Answer 1

a). Zn + 2Cl^- = ZnCl₂ + 2e^-

Ni(NO₃)₂ + 2e^- = Ni²⁺ + 2(NO₃)₂

b). Zn = Zn²⁺ + 2e^-

Ni = Ni²⁺ + 2e^-

Zn + Ni²⁺ $\to$ Zn²⁺ + Ni

c). Zn(s) ZnCl₂(s) Cl^-(aq) Ni(NO₃)₂(s) Ni(s)

d). $\phi$ (Zn) = -0.762B

$\phi$ (Ni) = -0.257B

0.762+0.257 = 1.019B