Question #160655

Calculate the pH of the following salts:a) 0.12 M NaNO2 b) 0.10 M CH3NH3Cl c) .45 M NaOCl?

1
Expert's answer
2021-02-03T07:08:03-0500

a)NaNO2_2 is a mixture of HNO2_2 and NaOH

Pk_k a of HNO2_2 =3.15

pH=7+1/2[Pka+logC]pH=7+1/2[3.15+log(0.12)]pH=8.16pH= 7+1/2[Pka+logC]\\ p^H=7+1/2[3.15+log(0.12)]\\ p^H=8.16


b)CH3NH3Cl is a salt of strong acid and weak base.

pH=7-1/2[Pkb+logC]

p^H=7-1/2[3.34+log(0.1)]\\

p^H= 5.83


c) NaOCl is a salt of strong base and weak acid

pH= 7+1/2[Pka+logC]\\

p^H=7+1/2[7.53+log(0.45)]\\

p^H=10.59



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