Calculate the molarity when 250 g of C6 H12 O6 is dissolved in 2500 ml of water.
M(C6H12O6) = 180 g/mol
n(C6H12O6) =250180=1.388 mol= \frac{250}{180} = 1.388 \;mol=180250=1.388mol
Proportion:
1.388 mol – 2500 mL
x – 1000 mL
x=1.388×10002500=0.55 Mx = \frac{1.388 \times 1000}{2500} = 0.55 \;Mx=25001.388×1000=0.55M
Answer: 0.55 M
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