Calculate the molality when 100 g of benzene(C 6 H 6 ) is dissolved in 500 g of hexane
(C 6 H 14 ).
Mass of benzene(solute)= 100g
Mass of hexane(solvent)= 500g = 0.5Kg
Molar mass of benzene= 78g/mol
Mole of benzene= mass/molar mass
Mole of benzene= 100/78= 1.28mol
Molality= moles of solute/1Kg of solvent
Molality= 1.28/0.5
Molality= 2.56 molal
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