How many grams of Sodium Hydroxide is needed to produce 242g of table salt (NaCl)?
Fe + NaOH ---> Fe (OH)3 +NaCl
FeCl3 + 3NaOH ---> Fe (OH) 3 + 3NaCl
(NaCl) = m/M= 242/58,5=4.14 mol
(NaCl)/3=(NaOH)/3 (NaOH)= (NaCl)= 4.14 mol
m(NaOH)=*M=4.14*40=165.6 g
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