Question

How many grams of diethyl ether are formed from 0.55 mole of ethanol?

Answer 1

2C₂H₅OH → (C₂H₅)₂O + H₂O

According to the reaction:

n((C₂H₅)₂O) = $\frac{1}{2}$ n(C₂H₅OH) = $\frac{1}{2} \times 0.55 = 0.275 \;mol$

M((C₂H₅)₂O) = 74.12 g/mol

$m = n \times M$

m((C₂H₅)₂O) $= 0.275 \times 74.12 = 20.38 \;g$

Answer: 20.38 g