How many grams of diethyl ether are formed from 0.55 mole of ethanol?
2C2H5OH → (C2H5)2O + H2O
According to the reaction:
n((C2H5)2O) = "\\frac{1}{2}" n(C2H5OH) = "\\frac{1}{2} \\times 0.55 = 0.275 \\;mol"
M((C2H5)2O) = 74.12 g/mol
"m = n \\times M"
m((C2H5)2O) "= 0.275 \\times 74.12 = 20.38 \\;g"
Answer: 20.38 g
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