How many moles are in 1.29 x 1024 hydrogen atoms in HF?
1 mol contains 6.022×10236.022 \times 10^{23}6.022×1023 atoms.
Proportion:
1 mol – 6.022×10236.022 \times 10^{23}6.022×1023
x - 1.29×10241.29 \times 10^{24}1.29×1024
x=1×1.29×10246.022×1023=2.14 molx = \frac{1 \times 1.29 \times 10^{24}}{6.022 \times 10^{23}} \\ = 2.14 \;molx=6.022×10231×1.29×1024=2.14mol
Answer: 2.14 mol
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