Question

What mass of sodium glycolate should be added to 400 ml of 1.00 M glycolic avid yo produce a buffer solution witj a ph of 4

Answer 1

for acid buffer mixture:

$рН = рКа– lg(Сacids/Сsalts)$

$4 = 3.83– lg(Сacids/Сsalts)$

$lg(Сacids/Сsalts)=-0.17$

$(Сacids/Сsalts)=0.676$

$(1/Сsalts)=0.676$

Сsalts=1.479

$m salts = Сsalts\times V(s)\times М = 1.479\times 0,4\times98.0332=57.996$