Answer to Question #159868 in General Chemistry for Maddie

Question #159868

How many molecules are in 127.39 g of SO₃?

Expert's answer

n(SO₃)=127.39/80.066=1.591 mol

N(SO₃)= 1.591*6.022*10²³=9.581*10²³ molecules

Answer: 9.581*10²³ molecules

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