1.0 mole of a gas occupies a volume of 22.4 L gas at 0°C and 1 atm. What would be the volume of 7.5 mol of the gas at the same temperature and pressure?
P1V1/n1T1=P2V2/n2T2P1V1/n1T1=P2V2/n2T2P1V1/n1T1=P2V2/n2T2
1∗22.4/1∗273=1∗x/7.5∗2731*22.4/1*273=1*x/7.5*2731∗22.4/1∗273=1∗x/7.5∗273
0.08=x/2047.50.08= x/2047.50.08=x/2047.5
x=163.8Lx = 163.8 Lx=163.8L
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