A given sample if gas occupies 75 mL at 2.5 atm. The pressure is increased to 8.1 atm while the temperature remains constant. What is the new volume of the gas?
According to Boyle's Law
P1V1 = P2V2 = k(Constant) at constant temperature
Solving for V2 becomes;
V2 "=\\dfrac{P1V1}{P2}"
Since;
P1=2.5atm
V1=75mL
P2=8.1atm
V2=?
Thus,
"V2=\\dfrac{2.5atmx75mL}{8.1atm} = 23.148mL"
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