Answer to Question #159535 in General Chemistry for Lali

Question

How much CaCl₂ would be required to make 50.0mL of a solution with 0.75 M Cl^- ion? (Use 1.00g/mL as the density for solution and water as the full volume of solution)

Answer 1

Molarity = no. of moles/volume

no. of moles = 0.75 x 0.05L = 0.0375 moles

gram of CaCl₂ = 0.0375 x 110.98 = 4.168 g