Question

Exactly 100 pounds of cane sugar (C12H0O11) were accidentally discharged into a small

stream saturated with oxygen from the air at 25°C. How many liters of this water could

be contaminated to the extent of removing all the dissolved oxygen by biodegradation?

Answer 1

C12H22O11 + 12O2 ------->12 CO2 + 11H2O

100 pounds =45359.2 gms

now, 342 gm of C12H22O11 gives 198 gms of h20

45359.2 gms gives = 45359.2 $\times$ $\frac{198}{342}$ = 26260.59 gm H20

26260.59 gm of H2O = 26.26 liters of H2O

hence 26.26 liters of water is contaminated