Exactly 100 pounds of cane sugar (C12H0O11) were accidentally discharged into a small
stream saturated with oxygen from the air at 25°C. How many liters of this water could
be contaminated to the extent of removing all the dissolved oxygen by biodegradation?
C12H22O11 + 12O2 ------->12 CO2 + 11H2O
100 pounds =45359.2 gms
now, 342 gm of C12H22O11 gives 198 gms of h20
45359.2 gms gives = 45359.2 "\\times" "\\frac{198}{342}" = 26260.59 gm H20
26260.59 gm of H2O = 26.26 liters of H2O
hence 26.26 liters of water is contaminated
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