A given aqueous solution has a density of x g/mL and y% solute by mass. Derive the mathematical equation relating the molarity of the solution, M, to the molality of the solution,m
Molarity= moles of solute/litres of solution
Molarity= moles of solute/1000ml of solution
Now, recall that
Mole= mass/molar mass
Molarity= mass/molar mass ÷ 1000ml
Molarity = Mass/molar mass x1/1000ml
Molarity= mass/1000ml × 1/molar mass
Making mass the subject of the formula
Mass= molarity x molar mass x 1000ml---------------(eq1)
Also,
Molality= mass of solute/1000g solvent
Making mass the subject of the formula
Mass= molality x 1000g------(eq2)
Replace eq1 in eq2
Molarity x molar mass 1000ml= molality x 1000g
Molarity= molality/molar mass x 1000g/1000ml
molarity= molality/molar mass x mass of solvent (g)/volume of solution(ml)
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