How many moles of Na2S2O3 are needed to react with 0.04 moles of C12?
A. 0.10 mol Na2S2O3
B. 0.20 mol Na2S2O3
C. 0.30 mol Na2S2O3
D. 0.40 mol Na2S2O3
E. 0.50 mol Na2S2O3
First of all, there is no correct answer in the multiple choices given.
The correct answer is 0.01 moles of Na2S2O3
Because the balanced equation for the implied reaction is;
Na2S2O3 + 4Cl2 + 5H2O "\\to" 2NaHSO4 + 8HCl
Thus, the mole ratio of Na2S2O3:Cl is 1:4
Moles of Na2S2O3 "=\\dfrac{1}{4}x0.04 = 0.01moles" of Na2S2O3
Comments
Leave a comment