The germanium (Ge) in steel production is normally reduced using C. If 34 mol GeO2 and 6.2 mol C are mixed, what is the limiting reagent? Use masses, Ge-72.64, O-16, C-12
GeO2 + C --> Ge + CO2
The limiting reagent of the reaction is C. Because according to the reaction ratio GeO2 to C is 1:1.
So as a result we can get only 6.2 mol Ge
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