Answer to Question #158793 in General Chemistry for Bamigboye sambiat

Question

Methane molecules in 112cm³ of methane are standard temperature and pressure

Answer 1

Volume = 112 cm³ = 112/1000 = 0.112 L

Standard Temperature and pressure = 273 K and 1 atm

Using Ideal gas equation,

PV = nRT

Where, P = pressure

V = Volume

n = moles

R = Gas constant = 0.0821atm-L/mol-K

T = Temperature

n = PV/RT

= 1.0×0.112/0.0821×273

= 0.0050 mol

Number of molecules = mole(n) × N_A

N_A isAvogadro Number = 6.022×10²³

Number of Methane molecules = 0.0050×6.022×10²³

= 3.00×10²¹ molecules

[So, Methane molecules = 3.00×10²¹ molecules]