Answer to Question #158649 in General Chemistry for teeeeeeera

Question

What percentage of the mass of the isotope carbon-12 do its neutrons contribute?

proton = 1.0073 amu

neutron = 1.0087 amu

electron = 5.4858×10^-4 amu

.............%

Answer 1

There are 6 protons, neutrons and electrons in the carbon-12 atom. Thus, the mass percentage of neutrons equals:

6*1.0087/(6*1.0087+6*1.0073+6*5.4858*10^-4)=0.50021110822=50,021110822%.

Solution: 50,02%.