What is 8.42 grams of sodium nitrate in moles
Moles of NaNO3 = MassofNaNO3MolarMassofNaNO3\dfrac{Mass of NaNO3}{Molar Mass of NaNO3}MolarMassofNaNO3MassofNaNO3
=8.42g84.9947g/mol=0.0991moles=\dfrac{8.42g}{84.9947g/mol} = 0.0991 moles=84.9947g/mol8.42g=0.0991moles
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