Question

What is the boiling point elevation of a solution that contains 40.5 grams of glycerol in 100 g of water?

Answer 1

$$\Delta T=E*Cm$$

$\Delta T$ - boiling point elevation; K

E - Ebulioscopic constant for water; E=0.52 K*kg/mol

Cm - mol/kg.

$$Cm=m*100/(M*m(H2O))$$

$$Cm=40.5*1000/92/100=4.4 mol/kg$$

$$\Delta T=0.52*4.4=2.288 K$$