Answer to Question #157123 in General Chemistry for afaf

General Chemistry

Question #157123

A 5.2kg piece of iron at 28.6°C absorbs 35.0kJ of energy. What is its final temperature?

Expert's answer

Q=mc∆T. ∆T=Q/mc = 35000/5200 x 0.444 = 15,1593902.

28.6 + 15,1593902 = 43,7593902 °C

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