Answer to Question #157087 in General Chemistry for Diamond

Question

The temperatures on the inside and outside surface of a wall are 20 degrees * C and 5 degrees * C respectively The wall is 8 m wide4 m high and 0.2 m thick. The thermal conductivity is 0.3W / m * o * K

what is the heat flux through the wall?

Answer 1

k= 0.3 W/m K

ΔT = 20 – 5 = 15 ºC

$S = 8 \times 4 = 32 \;m^2$

A = 0.2 m

$q = \frac{ΔT}{A/kS} \\ = \frac{15}{0.2/(0.3 \times 32)} \\ = 720 \;W$

Answer: 720 W