If 493.45 grams of CO2 are produced, how many grams of C2H2 were reacted?
C2H2 +2.5O2 = 2CO2 + H2O
n(CO2)= 493.45/44=11.215 mole
n(C2H2)=11.215/2=5.61 mole
m(C2H2)=5.61*(12+12+1+1)=145.86 grams
Answer: 145.86 grams of C2H2 reacted.
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