Question

If 196g of water is at 38^oC, and a copper block at 118^oC is added to it, and the final temperature of the mixture is 62^oC, what is the mass of the copper?

Answer 1

Q= mc∆T.

Q= 196 x 4.18 x ( 62-38) = 19662.72

m= Q/c∆T = 19662.72/0.39 x (118-62) = 900,307693.