Answer to Question #156593 in General Chemistry for faith hurt

Question

Using your target mass of CO2, calculate the mass of sodium bicarbonate, NaHCO3, you would need to produce it. The target mass is 0.50g and i need to solve it with a three step bracket.

Answer 1

Suppose we reacted the NaHCO3 solution with an HCl solution to produce the CO2. Then our balanced equation would be;

HCl_(aq) + NaHCO_3(aq) $\implies$ NaCl_(aq) + H₂O_(l) + CO_2(g)

Converting the target mass of CO2 into moles we shall have;

Moles of CO2 $=\dfrac{Mass of CO2}{MM of CO2} = \dfrac{5.0g}{44.01g/mol} = 0.1136 moles$

From the balanced equation, the mole ratio of CO₂:NaHCO₃ = 1:1

Thus, moles of NaHCO₃ $=\dfrac{1}{1}x0.1136mol = 0.1136mol$

Converting moles of NaHCO₃ to mass;

Mass of NaHCO₃ = moles of NaHCO₃ x Molar Mass of NaHCO₃

= 0.1136mol x 84.007g/mol

= 9.544g