Question

Using your target mass of CO2, calculate the mass of sodium bicarbonate, NaHCO3, you would need to produce it. The target mass is 0.50g and i need to solve it with a three step bracket.

Answer 1

Suppose we reacted the NaHCO3 solution with an HCl solution to produce the CO2. Then our balanced equation would be;

HCl_(aq) + NaHCO_3(aq) $\implies$ NaCl_(aq) + H₂O_(l) + CO_2(g)

Converting the target mass of CO2 into moles we shall have;

Moles of CO2 $=\dfrac{Mass of CO2}{MM of CO2} = \dfrac{5.0g}{44.01g/mol} = 0.1136 moles$

From the balanced equation, the mole ratio of CO₂:NaHCO₃ = 1:1

Thus, moles of NaHCO₃ $=\dfrac{1}{1}x0.1136mol = 0.1136mol$

Converting moles of NaHCO₃ to mass;

Mass of NaHCO₃ = moles of NaHCO₃ x Molar Mass of NaHCO₃

= 0.1136mol x 84.007g/mol

= 9.544g