How many joules of heat are absorbed when 70.0 grams of water is completely vaporized at its boiling point?
water enthalpy of vaporization is 40.65 kJ/mol
n(H2O) = (70 g)/(18 g/mol) = 3.8889 mol
"\\Delta"H = 3.8889*40.65 = 158.0833 kJ = 158083.3 J
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