A 0.300-kg piece of iron initially at 315 ºC is dropped into 0.400 L of water initially at 530ºR. Assuming that all heat transfer occurs between the iron and the water, calculate the final temperature.
The heat change of water is equal to the heat change of iron.
So,
"0.3*1000*0.45(273+315-T)=400*4.18*(T-(530+273))\\newline\n135(588-T)=180(T-803)\\newline 144540-79380=45T\\newline 65160=45T\\newline T=1448K \\newline The\\ final\\ temperature\\ is\\ 1448k" "In\\ degrees\\ =1175degrees"
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