F 100.0 g of iron three hydroxide is mixed with 80.0 g of sulfuric acid acid what will be the limiting reactant
The balanced equation for the reaction;
2Fe(OH)3 + 3H2SO4 "\\to" Fe(SO4)3 + 6H2O
Moles of Iron(III)hydroxide available
1mole "\\implies" 107g
? "\\implies" 100g
"=\\dfrac{1molx100g}{107g}"
= 0.9346mol
Moles of H2SO4 required to completely react with 100g of Iron (III) hydroxide;
Mole ratio of Fe(OH)3 : H2SO4 = 2:3
Moles of H2SO4 "=\\dfrac{3}{2} x0.9346 = 1.4019mol"
Moles of H2SO4 available "= \\dfrac{mass}{RFM} = \\dfrac{80g}{98g\/mol} = 0.8163mol"
Therefore, the moles of H2SO4 available are less than required, hence H2SO4 is the limiting reagent
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