A certain grade of coal contains 1.7 % S. Assume the burning of S compounds can be presented by the following equation:
S + O2 → SO2
Calculate the amount of the pollutant SO2 gases emitted in the atmosphere, per ton (1,000 kg,) of coal burned if the process is 79% efficient.
At first, the mass of S in 1 ton of coal may be calculated:
m(S)=1000×0.017=17(kg)=17000(g).
Theoretically, according to the chemical equation, from one mol of S one mol of SO2 is obtained:
n=m/M
n(SO2)=n(S)=17000/32=531.25(mol).
On practice:
n(SO2)=531.25×0.79=419.6875(mol).
m=n×M
M(SO2)=32+2×16=64(g/mol)
m(SO2)=419.6875×64=26860(g)=26.86(kg).
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