Answer to Question #155288 in General Chemistry for izeria

General Chemistry

Question #155288

At what temperature will 0.654 moles of neon gas occupy 12.30 liters at

1.95 atmospheres?

Expert's answer

Using the formula PV=nRT

T=PV/nR

T=1.95×12.3/0.654×0.0821

T=447K

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