Question

the vapor pressures of pure propyl alcohol and isopropyl alcohol are 21.0 mmHg and 45.2 mmHg. respectively, above a solution in which the mole fraction of isopropyl alcohol is 0.750

Answer 1

Pressure is d_irectly proportional to Mole

Therefore,

P = kn

k= P/n

P₁/n₁ = P₂/n₂

21.0 mmHg / x = 45.2 mmHg/0.750

x = (21.0 mmHg * 0.750) / 45.2 mmHg

x= 0.35 (pure propyl alcohol  mole ratio)