the vapor pressures of pure propyl alcohol and isopropyl alcohol are 21.0 mmHg and 45.2 mmHg. respectively, above a solution in which the mole fraction of isopropyl alcohol is 0.750
Pressure is directly proportional to Mole
Therefore,
P = kn
k= P/n
P1/n1 = P2/n2
21.0 mmHg / x = 45.2 mmHg/0.750
x = (21.0 mmHg * 0.750) / 45.2 mmHg
x= 0.35 (pure propyl alcohol mole ratio)
Comments
Leave a comment