Hydrogen gas can be produced by the reaction of hydrochloric acid with aluminum metal. How many grams of aluminum would be needed to fill-up a 250-mL container with hydrogen gas if the density of hydrogen gas is 0.84 g/L if the yield is only 75%.
3HCl + Al gives AlCl3 + 1.5H2
density = mass/volume
0.84g/L = mass/0.25L
mass = 0.84×0.25 = 0.2125g
Percentage yield = "\\frac{obtained yield}{theoreticalyield}" × 100
75 = "\\frac{0.2125}{theoreticalyield}" × 100
theoretical yield = (100×0.2125)/75 = 0.2833g
mass of aluminum required = 0.2833/1.5
= 0.1888g
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