Find the mass of sodium trioxoarbonate(IV) needed to give 22.4dm^3 of carbon(IV) oxide at stp in this reaction
Na2Co3 + 2Hcl --> 2NaCl + Co2 + H2O
(Na=23, O=16, C= 12, molar volume of a gas at stp= 22.4dm^3)
sodium trioxoarbonate(IV) needed to give 22.4dm^3 of carbon(IV) oxide at stp in this reaction
Na2Co3 + 2Hcl --> 2NaCl + Co2 + H2O
(Na=23, O=16, C= 12, molar volume of a gas at stp= 22.4dm^3)
Mole ratio = 1:2:2:1:1
Mass of Co2 = 44g
1 mole = 44g
Therefore 22.4dm3 = 1 mole
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