Normality = no. of equivalent/volume of solution
0.48N = (No. of equivalent/0.25L)
no. of equivalent = 0.12
no. of moles / n-factor = 0.12
no. of moles = 0.12× 3 = 0.36
mass/molar mass = 0.36
mass = 0.36×342 = 123.12gram
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