Question

calculate the grams of solute that must be dissolved in 350 g of water in the preparation of a 15.0% potassium sulfate solution.

Answer 1

% = $\frac{m_{K_2SO_4}}{m_{K_2SO_4}+m_{H_2O}}$ 100%

15% = $\frac{m_{K_2SO_4}}{m_{K_2SO_4}+350}$ 100%

$m_{K_2SO_4}$ = 0.15($m_{K_2SO_4}$ + 350)

$m_{K_2SO_4}$ = 61.8 g