Question

145.3 g of Sodium phosphate reacted completely with Calcium chloride. The reaction yielded to new compounds.

(note: Na=23.0g/mol, P=31.0g/mol, O=16.0g/mol, Ca=40.0g/mol, Cl=35.0g/mol)

Please find the compounds.

Answer 1

3CaCl₂+ 2Na₃PO₄= Ca₃(PO₄)₂ + 6NaCl

calcium phosphate, sodium chloride

find the masses of the obtained compounds:

$n (Na3PO4)=\frac{m}{M}=\frac{145.3}{164}=0.89$

masses ofCa₃(PO₄)₂

$\frac{0.89}{2}=\frac{x}{1}$

x=0.445

$m=M\times n=0.445*310=137.95$

masses of NaCl:

$\frac{0.89}{2}=\frac{x}{6}$

x=2.67

$m=M\times n=2.67*58=154.86$