Cu(s) + AgNO3(aq) ---> CuNO3(aq) + Ag(s)
How many grams of silver would be produced if you began with 10 grams of copper?
MM(Cu) = 63.5 g/mol
n(Cu)=1063.5=0.157 moln(Cu) = \frac{10}{63.5} = 0.157 \;moln(Cu)=63.510=0.157mol
n(Ag) = n(Cu) = 0.157 mol
MM(Ag) = 107.8 g/mol
m(Ag)=0.157×107.8=16.92 gm(Ag) = 0.157 \times 107.8 = 16.92 \;gm(Ag)=0.157×107.8=16.92g
Answer: 16.92 g
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