Mass of MgSO4 at saturated solution = density*volume = 100ml*1.21gcm-3 = 121 g
MgSO4 + BaCl2 = MgCl2 + BaSO4
n(MgSO4) = 121g/120g/mol = 1 mol
n(BaCl2) = 25g/208g/mol = 0.12 mol
According to the equation 0.12 mol of MgSO4 reacts with BaCl2, then
m(MgSO4) = 0.88mol*120g/mol = 105.6 g will be dissolved in 100g of solution at room temperature
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