Question #152190

400cm3 of helium gas effuses from a pourous container in 20 sec. How long will SO2 gas take to effuse from the same container?

Expert's answer

Time taken for Helium gas to effuse = 10 sec


Pressure, Volume, Temperature is constant since the same container is used.


Molar mass of Helium = 4 g/mol

Molar mass of SO2 = 64g/mol


According to graham's law of diffusion/effusion

The rate of diffusion of a gas is proportional to the square root of the inverse of the molar mass.


r=1Mr = \sqrt{\dfrac{1}{M}}



rHerSO2=MSO2MHe\dfrac{r_{He}}{r_{SO_2}} = \sqrt{\dfrac{M_{SO_2}}{M_{He}}}


but, the rate is inversely proportional to time


tSO2tHe=MSO2MHe\dfrac{t_{SO_2}}{t_{He}} = \sqrt{\dfrac{M_{SO_2}}{M_{He}}}


tSO210=644\dfrac{t_{SO_2}}{10} = \sqrt{\dfrac{64}{4}}


tSO210=4\dfrac{t_{SO_2}}{10} = 4


tSO2=40t_{SO_2} = 40


Therefore, it will take 40 seconds for SO2SO_2 gas take to effuse from the same container.


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