Answer to Question #152126 in General Chemistry for molly

Question #152126

how many particles are present in 0.886 liters of unknown gas at standard temperature and pressure?

Expert's answer

N =( V/V_M) * N_A= (0.886/22.4)*6.02*10²³=2.38*10²²;

Answer: 2.38*10²³ particles

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