Answer to Question #152094 in General Chemistry for Shazreen Keisha Shah

Question #152094

How would I solve a question like this: 6.21 g of iron(III) sulfate was dissolved in a solution of 300 mL. What is the concentration, in mol/L, of the sulfate ion in solution?

Expert's answer

We can solve this using the formula; n=CV

But we need to find the number of moles first Using the formula; mole=mass/molar mass

Molar mass of Iron(iii)sulfate=400g/mol

Mole=6.21/400=0.016moles

Coverting 300mL to litres we have 0.3L

If n=CV ,then C=n/V

C=0.016/0.3

C=0.053M

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Assignment Expert

04.01.21, 15:12

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Shazreen Keisha Shah

02.01.21, 22:49

What is the molar mass, in g/mol, of 0.475g of an ideal gas that has a volume of 450ml at 175kPA and 15°C? Round your answer to two sig-figs.

Keisha

02.01.21, 22:48

What is the volume of 26.311g of butane gas (C4H10), at 22.7°C and 125.1 kPa? Round your answer to the nearest thousandth.