Question

How many grams of HCl are needed to react with 0.70 moles of Al

Answer 1

The reaction between HCl and Al is

6HCl + 2Al ----> 3H₂ + 2AlCl₃

2 moles of Al reacts with 6 moles of HCl

1 mole of Al reacts with (6/2) moles of HCl

0.70 mole of Al reacts with (6/2) moles of HCl

= (6/2)×0.7 moles.

= 2.1 moles

Molar Mass of HCl = 36.5 g/mol

Mass of 2.1 moles of HCl = (36.5×2.1)g

= 76.65 g

Hence, 76.65 grams of HCl are needed to react with 0.70 moles of Al