Answer to Question #151857 in General Chemistry for Molly

Question

how many milligrams are present in 9.7748 x 10^22 molecules of chlorine gas at STP?

Answer 1

Solution:

Molar mass of Cl₂ 70,914 g/mol

m = n×M

n = 9.7748×10²² / 6.0221×10²⁴ = 0,016 mol Cl₂

m = 0.016× 70.914= 1.135 g = 1 135 mg

Answer: mass of Cl₂ is 1 135 mg.